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〈sin^2xDx

基 喇cos2x=1-2(sinx)^2誼(sinx)^2=1/2-cos2x/2 〈(sinx)^2dx =〈 1/2-cos2x/2 dx =x/2-sin2x/4 + C

sin(t^2) 議圻痕方頁掲兜吉痕方音嬬喘塋襲躊鑛襲輅 。

〈 dx/(sinx)^2 =〈 (cscx)^2dx = -cotx + C

(cosx)'=-sinx 軸dcosx=-sinxdx sinxdx=-dcosx

喘鑑裏蛍

聞喘巷塀1-2sin²2x=cos4x 軸sin²2x=(1-cos4x)/2 侭參〈sin²2xdx =〈(1-cos4x)/2 dx =x - 1/8 *sin4x +CC葎械方

蛍裂狛殻泌夕侭幣協持蛍議云嵎祥頁匯倖方。

朔中sin椎匯醪科敗攘崢孤和陦

〈πsin²xdx=π〈[(1-cos2x)/2]dx=π〈(1/2)dx-π〈(1/4)*(cos2x)d2x =π[x/2-(1/4)sin2x] 圻持蛍=π[π/2-(1/4)sin2π]- =π²/2

〈x²sin²x dx =(1/2)〈x²(1-cos2x) dx =(1/2)〈x² dx - (1/2)〈x²cos2x dx =(1/2)(1/3)x³ - (1/2)(1/2)〈x² d(sin2x) =(1/6)x³ - (1/4)x²sin2x + (1/4)〈sin2x*2x dx =(1/6)x³ - (1/4)x²sin2x...

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