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八除以1+7括号括回列脱式计算怎么做

八除以1+7括号括回列脱式计算怎么做 8÷(1+7) =8÷8 =1. 请采纳,谢谢.

7/8-括号5/12+1/6括回脱式计算 (7/8)-(5/12+1/6) =(7/8)-(7/12) =(21/24)-(14/24) =7/24.

7×2÷2+括号5+7括号乘5÷2+5×1÷2脱式计算 7×2÷2+括号5+7括号乘5÷2+5×1÷2 =7*2÷2+(5+7)*5÷2+5*1÷2 =7+30+2.5 =39.5 直接计算

6/7-6/7×(2/3+1/9) =6/7-6/7×7/9 =6/7×(1-7/9) =6/7×2/9 =4/21

1/2 2/3×括号3/4-1/6括号除以7/9脱式计算 解: 1/2+ 2/3×(3/4-1/6)除以7/9 =1/2+2/3×7/12÷7/9 =1/2+1/2 =1

(-1-1/4×8/9)÷7/9 =(-1×9/7)-(1/4×9/7)×(8/9×9/7) =-9/7-9/28×8/7 =-36/28-9/28×8/7 =-36/28-36/98 =-63/49-18/49 =-81/49

八分之7-括号1/3-4分之一括号怎么写脱式计算 八分之7-括号1/3-4分之一括号 =7/8-1/12 =21/24-2/24 =19/24

2/5×[1/5+8/21÷(4/7)] =2/5x(1/5+2/3) =2/5x(13/15) =26/75

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