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程序设计输入四个数分别为两个复数的实部和虚部....

#include "stdio.h"int main(int argv,char *argc[]){double a,b,aa,bb;printf("Input a, b, aa & bb(R:)...\n");scanf("%lf%lf%lf%lf",&a,&b,&aa,&bb);printf("%f%+fi + %f%+fi = %f + %fi\n",a,aa,b,bb,a+b,aa+bb);return 0;}运行样例:

import java.util.Scanner; public class Complex { private int realPart; private int imagPart; public int getRealPart() { return realPart; } public void setRealPart(int realPart) { this.realPart = realPart; } public int getImagPa...

#include#includeint main() {std::complex val1(1.5,0.8);std::complex val2(1.2,0.5);std::cout

不需要循环, A = [1 -1 3 2 -4 5 1 -1 0 2]; B = A(1:2:end) + A(2:2:end)*1i; 即可实现奇偶位组合成复数

#includefloat result_real,result_imag;void complex_prod(float x1, float y1,float x2,float y2) ; //声明函数int main(void){float imag1,imag2,real1,real2;printf("enter 1st complex number(real and imaginary):");scanf("%f%f",&real1,...

#include#includeusing namespace std;typedef float REAL;#define MAX_BUF_LEN 256typedef struct COMPLEX{REAL r;// 实部REAL i;// 虚部};bool ParseComplex(COMPLEX * cp, const char * strCplx, const int len){memset(cp, 0, sizeof(COMPL...

#include "string.h" #include "iostream.h" class complex { private: float x,y; public: complex(float x, float y) { this->x=x; this->y=y; cout

#include using namespace std; class complex { double sb; double xb; public: void display(); complex(double s,double x) //构造函数 { sb=s; xb=x; } }; void complex::display() { cout

#include //定义结构体变量类型 struct fushu { int sb; //存储复数实部 int xb; //存储复数虚部 //创建fhshu结构体类型默认值(又称结构体类型构造函数) fushu() { sb = 0; xb = 0; } //创建fhshu结构体类型初始化函数(又称结构体类型构造函数) ...

因为根据复数定义,复数是由实部和虚部组成,实部和虚部不能进行加减运算而结合,只能进行乘除运算,所以要想一个复数为零,必须实部和虚部同时为零。这也是两个复数比较时,如果两个复数相等,也只能实部实部相等,虚部虚部相等!

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