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解方程 x%7x69=5x1.2x

X-7×69=5×1.2X X-483=6X 6X-X=-483 5X=-483 X=-483÷5 X=-96.6

(1)x(3+5x)=0,∴x1=0,x2=-?35;(2)(3-x)(7x+4)=0,∴x1=3,x2=-47;(3)去分母整理得4x2-16x+12=0,即x2-4x+3=0,(x-3)(x+1)=0,∴x1=3,x2=-1,经检验x1=3,x2=-1是原方程的根.所以原方程的根为x1=3,x2=-1.

解:1/5x+500=40%x 1/5x+500=2/5x 2/5x-1/5x=500 1/5x=500 x=500*5 x=2500

因题干条件不完整,缺题干,不能正常作答

1/(x^2+x)+1/(x^2+3x+2)+1/(x^2+5x+6)+1/(x^2+7x+12)+1/(x^2+9x+20) =1/x(x+1)+ 1/(x+1)(x+2) + 1/(x+2)(x+3)+ 1/(x+3)(x+4)+ 1/(x+4)(x+5) =[1/x - 1/(x+1)]+[1/(x+1) - 1/(x+2)]+[1/(x+2) - 1/(x+3)]+[1/(x+3) - 1/(x+4)]+[1/(x+4) - 1/...

(1)整理得:x2-4x=6,配方得:x2-4x+4=6+4,(x-2)2=10,x-2=±10,x1=2+10,x2=2-10;(2)整理得:7x2-x-13=0,b2-4ac=(-1)2-4×7×(-13)=365,x=1±3652×7,x1=1+36514,x2=1-36514.

①由原方程,得x2-4x=0,∴x(x-4)=0,∴x=0或x-4=0,解得,x1=0,x2=4; ②∵方程2x2-5x+1=0的二次项系数a=2,一次项系数b=-5,常数项c=1,∴x=?b±b2?4ac2a=5±174,解得,x1=5+174,x2=5?174; ③由原方程,得(x-1+2)2=0,即(x+1),+=0,解得,x1...

(1) 5x+2y=2 ① 7x-5y=34 ② ①×5+②×2得:39x=78,则:x=2 把x=2代入 ①,得:10+2y=2,得:y=-4 所以,方程组的解为:x=2,y=-4; (2) 8x+3y+2=0 ① 6x+5y+7=0 ② ①×5-②×3得:22x-11=0,则:x=1/2 把x=1/2代入①,得:4+3y+2=0,得:y=-2 所以,方程组...

17(2-3x)-5(12-x)=8(1-7x) 34-51x-60+5x=8-56x 94-46x=8-56x 56x-46x=8+94 10x=102 x=102÷10 x=10.2

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