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用C语言编写程序,用结构体的方法进行两个复数的相减

/* c = 1+i2 Press any key to continue */ #include struct Complex {double m_r;double m_i;};void main() {struct Complex c1 = {1.2,2.3},c2 = {0.2,0.3};struct Complex c;c.m_r = c1.m_r - c2.m_r;c.m_i = c1.m_i - c2.m_i;printf("c = %g...

#include #include typedef struct MyComplex { double real; double img; }mc; mc Plus(mc a,mc b) { mc result; result.real = a.real + b.real; result.img = a.img + b.img; return result; } mc Sub(mc a,mc b) { mc result; result.real =...

struct cp{ LDB r,i; }; inline cp operator +(cp a,cp b) {return((cp){a.r+b.r,a.i+b.i});}; inline cp operator -(cp a,cp b) {return((cp){a.r-b.r,a.i-b.i});}; inline cp operator *(cp a,cp b) {return((cp){a.r*b.r-a.i*b.i,a.i*b.r+a....

#include struct complex { int re; int im; }; void add(struct complex a, struct complex b, struct complex *c){ c->re=a.re+b.re; c->im=a.im+b.im;}void minus(struct complex a, struct complex b, struct complex *c){ c->re=a.re-b.re;...

void Input(struct Complex x)改为void Input(struct Complex *x) scanf("%d%d",x->r,x->i); 改为scanf("%d%d",&(x->r),&(x->i)); struct Complex a,b=(1,1),z,*p; 改为struct Complex a,b={.r=1; .i=1;},z,*p;

C++可以用类,然后重载运算符 C可以用struct来代替类,然后写相应函数来就行了,一回事 下面是随手写的,大概就这样子吧 struct complex{ int real; int imag; }a,b; complex Plus(complex a,complex b) { complex result; result->real = a->...

#define ARR_SIZE 20 typedef struct complex { int aNum; int bNum; }Complex; void Add(Complex *A, Complex *B) { A->aNum=A->aNum+B->aNum; A->bNum=A->bNum+B->bNum; } void Minus(Complex *A, Complex *B) { A->aNum=A->aNum-B->aNum; A->...

#include "stdafx.h"#include using namespace std;struct complex //定义一个复数结构体{ int real; //实数,数据类型根据自己的要求改吧 int imaginary; //虚数,同上 friend complex operator + (complex a, complex b); //重载运算符“+”,其...

#include using namespace std; struct Complex{ double real,imag; }; void Swap(Complex &c1,Complex &c2){ Complex t; t=c1; c1=c2; c2=t; } void main(){ Complex c1={1,2},c2={20,15}; Swap(c1,c2); cout

#include struct complex{ double re; double im;};struct complex add(struct complex c1, struct complex c2){ struct complex sum; sum.re = c1.re + c2.re; sum.im = c1.im + c2.im; return sum;}int main(void){ struct complex a, b, s; p...

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